User talk:Paul Wormer/scratchbook1: Difference between revisions

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</math>
</math>
which is the equation for a plane through a point ''A'' perpendicular to <font style="vertical-align: super;"><math>\overrightarrow{OA}</math></font>.
which is the equation for a plane through a point ''A'' perpendicular to <font style="vertical-align: super;"><math>\overrightarrow{OA}</math></font>.
===Three point representation===
===Three-point representation===
{{Image|Param2 plane.png|right|350px|<small> Fig. 2. Plane through points ''A'', ''B'', and ''C''.}}
{{Image|Param2 plane.png|right|350px|<small> Fig. 2. Plane through points ''A'', ''B'', and ''C''.</small>}}
Figure 2 shows a plane that by definition passes through the points ''A'', ''B'', and ''C''. The point ''P'' is an arbitrary point in the plane and the reference point ''O'' is not in the plane. Referring to figure 2 we introduce the following definitions
Figure 2 shows a plane that by definition passes through the points ''A'', ''B'', and ''C''. The point ''P'' is an arbitrary point in the plane and the reference point ''O'' is outside the plane. Referring to figure 2 we introduce the following definitions
:<math>
:<math>
\vec{a} = \overrightarrow{OA},\quad \vec{b} = \overrightarrow{OB},\quad\vec{c} = \overrightarrow{OC},\quad \vec{r} = \overrightarrow{OP}.
\vec{a} = \overrightarrow{OA},\quad \vec{b} = \overrightarrow{OB},\quad\vec{c} = \overrightarrow{OC},\quad \vec{r} = \overrightarrow{OP}.
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\vec{u} = \overrightarrow{AB}= \vec{b}-\vec{a} ,\quad  \vec{v} = \overrightarrow{AC}= \vec{c}-\vec{a}.
\vec{u} = \overrightarrow{AB}= \vec{b}-\vec{a} ,\quad  \vec{v} = \overrightarrow{AC}= \vec{c}-\vec{a}.
</math>
</math>
Any vector in the plane can be written as a linear combination of these two vectors. In particular,
Any vector in a plane can be written as a linear combination of two non-collinear vectors in this plane (this is also expressed as: any vector in a plane can be decomposed into components along  two non-collinear vectors). In particular,
:<math>
:<math>
\overrightarrow{AP}= \vec{r}-\vec{a} = \lambda \vec{u} + \mu\vec{v}.
\overrightarrow{AP}= \vec{r}-\vec{a} = \lambda \vec{u} + \mu\vec{v},\qquad \lambda,\mu \in \mathbb{R}.
</math>
</math>
The real numbers &lambda; and &mu; specify the direction of <font style="vertical-align: super;"><math>\overrightarrow{AP}</math><font>. Hence the equation for the position vector <font style="vertical-align: super;"><math>\vec{r}</math><font> of the arbitrary point ''P'' in the plane
The real numbers &lambda; and &mu; specify the direction of <font style="vertical-align: super;"><math>\overrightarrow{AP}</math></font>. Hence the following equation for the position vector <math>\vec{r}</math> of the arbitrary point ''P'' in the plane:
:<math>
:<math>
\vec{r} = \vec{a} + \lambda \vec{u} + \mu\vec{v}
\vec{r} = \vec{a} + \lambda \vec{u} + \mu\vec{v}
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is known as the ''point-direction representation'' of the plane. This representation is equal to the  ''three-point representation''  
is known as the ''point-direction representation'' of the plane. This representation is equal to the  ''three-point representation''  
:<math>
:<math>
\vec{r} = \vec{a}+ \lambda (\vec{b}-\vec{a}) + \mu(\vec{c}-\vec{a})
\vec{r} = \vec{a}+ \lambda (\vec{b}-\vec{a}) + \mu(\vec{c}-\vec{a}),
</math>
</math>
where <math>\vec{a}</math>,  <font style="vertical-align: top;"><math>\vec{b}</math></font>, and <math>\vec{c}</math> are the position vectors of the three points that define the plane.

Revision as of 08:07, 31 March 2010

Point-normal representation

PD Image
Fig. 1. Equation for plane. X is arbitary point in plane; and are collinear.

In analytic geometry several closely related algebraic equations are known for a plane in three-dimensional Euclidean space. One such equation is illustrated in figure 1. Point P is an arbitrary point in the plane and O (the origin) is outside the plane. The point A in the plane is chosen such that vector

is orthogonal to the plane. The collinear vector

is a unit (length 1) vector normal (perpendicular) to the plane which is known as the normal of the plane in point A. Note that d is the distance of O to the plane. The following relation holds for an arbitrary point P in the plane

This equation for the plane can be rewritten in terms of coordinates with respect to a Cartesian frame with origin in O. Dropping arrows for component vectors (real triplets) that are written bold, we find

with

and


Conversely, given the following equation for a plane

it is easy to derive the same equation. Write

It follows that

Hence we find the same equation,

where f , d, and n0 are collinear. The equation may also be written in the following mnemonically convenient form

which is the equation for a plane through a point A perpendicular to .

Three-point representation

PD Image
Fig. 2. Plane through points A, B, and C.

Figure 2 shows a plane that by definition passes through the points A, B, and C. The point P is an arbitrary point in the plane and the reference point O is outside the plane. Referring to figure 2 we introduce the following definitions

Clearly the following two non-collinear vectors belong to the plane

Any vector in a plane can be written as a linear combination of two non-collinear vectors in this plane (this is also expressed as: any vector in a plane can be decomposed into components along two non-collinear vectors). In particular,

The real numbers λ and μ specify the direction of . Hence the following equation for the position vector of the arbitrary point P in the plane:

is known as the point-direction representation of the plane. This representation is equal to the three-point representation

where , , and are the position vectors of the three points that define the plane.