Talk:Percentile: Difference between revisions
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imported>Peter Schmitt (→replacint WP: typo corrected) |
imported>Boris Tsirelson (→Not quite so: new section) |
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I replaced the WP import by a new article, and added an example (test results) previously inserted | I replaced the WP import by a new article, and added an example (test results) previously inserted | ||
by [[User:Anh Nguyen|Anh Nguyen]] (3rd revision, 10:11, 8 November 2006). [[User:Peter Schmitt|Peter Schmitt]] 16:03, 23 November 2009 (UTC) | by [[User:Anh Nguyen|Anh Nguyen]] (3rd revision, 10:11, 8 November 2006). [[User:Peter Schmitt|Peter Schmitt]] 16:03, 23 November 2009 (UTC) | ||
== Not quite so == | |||
The implication | |||
: <math> P(\omega = x) > 0 \Rightarrow | |||
P(\omega\le x) > {k\over100} \textrm{\ \ and \ \ } | |||
P(\omega\ge x) > 1-{k\over100} </math> | |||
is not always true; when ''k'' is at the left endpoint of the relevant interval, the first inequality is not strict; and when ''k'' is at the right endpoint of the relevant interval, the second inequality is not strict. In addition, I did not understand from the article, is ''k'' assumed to be integral, or not? If it is then these non-strict inequalities become more rare cases, but still possible. [[User:Boris Tsirelson|Boris Tsirelson]] 19:11, 26 November 2009 (UTC) | |||
Revision as of 13:11, 26 November 2009
Replacing WP
I replaced the WP import by a new article, and added an example (test results) previously inserted by Anh Nguyen (3rd revision, 10:11, 8 November 2006). Peter Schmitt 16:03, 23 November 2009 (UTC)
Not quite so
The implication
is not always true; when k is at the left endpoint of the relevant interval, the first inequality is not strict; and when k is at the right endpoint of the relevant interval, the second inequality is not strict. In addition, I did not understand from the article, is k assumed to be integral, or not? If it is then these non-strict inequalities become more rare cases, but still possible. Boris Tsirelson 19:11, 26 November 2009 (UTC)