Talk:Percentile: Difference between revisions
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imported>Boris Tsirelson (→Not quite so: new section) |
imported>Peter Schmitt (→Not quite so: indeed ....) |
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P(\omega\ge x) > 1-{k\over100} </math> | P(\omega\ge x) > 1-{k\over100} </math> | ||
is not always true; when ''k'' is at the left endpoint of the relevant interval, the first inequality is not strict; and when ''k'' is at the right endpoint of the relevant interval, the second inequality is not strict. In addition, I did not understand from the article, is ''k'' assumed to be integral, or not? If it is then these non-strict inequalities become more rare cases, but still possible. [[User:Boris Tsirelson|Boris Tsirelson]] 19:11, 26 November 2009 (UTC) | is not always true; when ''k'' is at the left endpoint of the relevant interval, the first inequality is not strict; and when ''k'' is at the right endpoint of the relevant interval, the second inequality is not strict. In addition, I did not understand from the article, is ''k'' assumed to be integral, or not? If it is then these non-strict inequalities become more rare cases, but still possible. [[User:Boris Tsirelson|Boris Tsirelson]] 19:11, 26 November 2009 (UTC) | ||
:: Thank you for spotting the ''p'''s. I changed from ''p'' to ''k'' and forgot them. | |||
:: Yes, I think that percentiles are used for integer ''k''. I am no statistician, so I cannot be absolutly sure. But I have two reasons to assume that integer values are the usual case (though everybody who understands them will understand arbitrary values): | |||
::: They are usually called "''k''-th percentile. | |||
::: For general probabilities there is the quantile. | |||
:: And, yes, I overlooked the special case in the inequality. It should be "or" instead of "and". | |||
:: [[User:Peter Schmitt|Peter Schmitt]] 00:57, 27 November 2009 (UTC) |
Revision as of 18:57, 26 November 2009
Replacing WP
I replaced the WP import by a new article, and added an example (test results) previously inserted by Anh Nguyen (3rd revision, 10:11, 8 November 2006). Peter Schmitt 16:03, 23 November 2009 (UTC)
Not quite so
The implication
is not always true; when k is at the left endpoint of the relevant interval, the first inequality is not strict; and when k is at the right endpoint of the relevant interval, the second inequality is not strict. In addition, I did not understand from the article, is k assumed to be integral, or not? If it is then these non-strict inequalities become more rare cases, but still possible. Boris Tsirelson 19:11, 26 November 2009 (UTC)
- Thank you for spotting the p's. I changed from p to k and forgot them.
- Yes, I think that percentiles are used for integer k. I am no statistician, so I cannot be absolutly sure. But I have two reasons to assume that integer values are the usual case (though everybody who understands them will understand arbitrary values):
- They are usually called "k-th percentile.
- For general probabilities there is the quantile.
- And, yes, I overlooked the special case in the inequality. It should be "or" instead of "and".
- Peter Schmitt 00:57, 27 November 2009 (UTC)