Noetherian ring: Difference between revisions
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Let <math>A</math> be a ring. The following conditions are equivalent: | Let <math>A</math> be a ring. The following conditions are equivalent: | ||
#The ring <math>A</math> satisfies an ascending chain condition on the set of its ideals: that is, there is no infinite ascending chain of ideals <math>I_0\subsetneq I_1\subsetneq I_2\subsetneq\ldots</math>. | #The ring <math>A</math> satisfies an [[ascending chain condition]] on the set of its ideals: that is, there is no infinite ascending chain of ideals <math>I_0\subsetneq I_1\subsetneq I_2\subsetneq\ldots</math>. | ||
#Every ideal of <math>A</math> is finitely generated. | #Every ideal of <math>A</math> is finitely generated. | ||
#Every nonempty set of ideals of <math>A</math> has a maximal element when considered as a partially ordered set with respect to inclusion. | #Every nonempty set of ideals of <math>A</math> has a maximal element when considered as a partially ordered set with respect to inclusion. |
Revision as of 05:53, 30 November 2008
Definition
Let be a ring. The following conditions are equivalent:
- The ring satisfies an ascending chain condition on the set of its ideals: that is, there is no infinite ascending chain of ideals .
- Every ideal of is finitely generated.
- Every nonempty set of ideals of has a maximal element when considered as a partially ordered set with respect to inclusion.
When the above conditions are satisfied, is said to be Noetherian. Alternatively, the ring is Noetherian if is a Noetherian module when regarded as a module over itself.
Useful Criteria
If is a Noetherian ring, then we have the following useful results:
- The quotient is Noetherian for any ideal .
- The localization of by a multiplicative subset is again Noetherian.
- Hilbert's Basis Theorem: The polynomial ring is Noetherian (hence so is ).