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The molar volume (symbol V_m) is the volume occupied by one mole of a substance at a given temperature and pressure. It is equal to the molecular mass (M) of the subtance divided by its density (ρ) at the given temperature and pressure:

$V_{\rm {m}}={M \over \rho }$

It has an SI unit of cubic metres per mole (m³/mol). However, molar volumes are often expressed as cubic metres per 1,000 moles (m³/kmol) or cubic decimetres per mol (dm³/mol) for gases and as centimetres per mole (cm³/mol) for liquids and solids.

If a substance is a mixture containing N components, the molar volume is calculated using:

$V_{\rm {m}}={\frac {\displaystyle \sum _{i=1}^{N}x_{i}M_{i}}{\rho _{mixture}}}$

where x _i is the mole fraction of the ith component, M _i is the molecular mass of the ith component and ρ_mixture is the mixture density at the given temperature and pressure.

When stating molar volume numerical values, it is important to also state the given conditions of temperature and pressure. Otherwise, the numerical values are meaningless.

Ideal gases

The ideal gas law equation can be rearranged to give this expression for the molar volume of an ideal gas:

$V_{\rm {m}}={V \over {n}}={{RT} \over {P}}$

Where in SI units:

P	= the gas absolute pressure, in Pa
n	= number of moles, in mol
Vm	= the gas molar volume, in m3/mol
T	= the gas absolute temperature, in K
R	= the universal gas law constant of 8.314472 m3·Pa·mol-1·K-1

Where in U.S. customary units:

P	= the gas absolute pressure, in psia
n	= number of moles, in lb-mol
Vm	= the gas molar volume, in ft3/lb-mol
T	= the gas absolute temperature, in degrees Rankine (°R)
R	= the universal gas law constant of 10.7316 ft3·psia·lb-mol-l·°R-1

Example calculations of ideal gas molar volumes:

• In SI metric units:

V_m = 8.314472 × 273.15 / 101,325 = 0.022414 m³/mol at 0 °C and 101,325 Pa absolute pressure = 22.414 m³/kmol at 0 °C (273.15 K) and 101.325 kPa absolute pressure

V_m = 8.314472 × 273.15 / 100,000 = 0.022711 m³/kmol at 0 °C and 100,000 Pa absolute pressure = 22.711 m³/kmol at 0 °C (273.15 K) and 100 kPa absolute pressure

• In customary USA units:

V_m = 10.7316 × 519.67 / 14.696 = 379.48 ft³/lb-mol at 60 °F (519.67 °R) and 14.696 psia

Notes:

• lb-mol is an abbreviation for pound-mol
• °R is degrees Rankine (an absolute temperature scale) and °F is degrees Fahrenheit (a temperature scale).
• °R = °F + 459.67
• The technical literature can be confusing because some authors often fail to explain whether they are using the universal gas law constant R, which applies to any ideal gas, or whether they are using the specific gas law constant R_s, which only applies to a specific individual gas. The relationship between the two constants is R_s = R / M, where M is the molecular mass of the gas.