User:Milton Beychok/Sandbox: Difference between revisions
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imported>Milton Beychok No edit summary |
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Note that the coding in EOE's "Velocity" article does not include any of the '''necessary''' reverse slashes '''\'''. | Note that the coding in EOE's "Velocity" article does not include any of the '''necessary''' reverse slashes '''\'''. | ||
And this is how it should be rendered in any articles: | And, in any event, this is how it should be rendered in any articles: | ||
<math>\mathbf{v} = \lim_{\Delta t \to 0}{{\mathbf{x}(t+\Delta t)-\mathbf{x}(t)} \over \Delta t}={\mathrm{d}\mathbf{x} \over \mathrm{d}t}.</math> | <math>\mathbf{v} = \lim_{\Delta t \to 0}{{\mathbf{x}(t+\Delta t)-\mathbf{x}(t)} \over \Delta t}={\mathrm{d}\mathbf{x} \over \mathrm{d}t}.</math> | ||
Revision as of 19:27, 16 September 2011
As currently rendered in the EoE's "Velocity" article:
<math>mathbf{v} = lim_{Delta t to 0}{{mathbf{x}(t+Delta t)-mathbf{x}(t)} over Delta t}={mathrm{d}mathbf{x} over mathrm{d}t}.</math>
This is the correct version of the LaTeX coding:
<math>\mathbf{v} = \lim_{\Delta t \to 0}{{\mathbf{x}(t+\Delta t)-\mathbf{x}(t)} \over \Delta t}={\mathrm{d}\mathbf{x} \over \mathrm{d}t}.</math>
Note that the coding in EOE's "Velocity" article does not include any of the necessary reverse slashes \.
And, in any event, this is how it should be rendered in any articles:
